### How to solve Simple Quadratic Equation in Java ?.

 Tweet Program to solve Simple Quadratic Equation in Java. ```import java.util.Scanner; public class Quadratic { public static void main(String[] args) { Scanner input = new Scanner(System.in); double a = 0; double b = 0; double c = 0; double discriminant = 0; double d = 0; System.out.print("Enter the value of a : "); a = input.nextDouble(); System.out.print("Enter the value of b : "); b = input.nextDouble(); System.out.print("Enter the value of c : "); c = input.nextDouble(); discriminant = (b * b - 4 * a * c); d = Math.sqrt(discriminant); if (discriminant >= 0.0) { System.out.println("First root of the equation : " +(-b + d) / (2.0*a)); System.out.println("Second root of the equation : " +(-b - d) / (2.0*a)); } else { System.out.println("The roots are not real numbers."); } } } ``` Output of the program :
Program to solve Simple Quadratic Equation in Java.

```import java.util.Scanner;

{
public static void main(String[] args)
{
Scanner input = new Scanner(System.in);

double a = 0;
double b = 0;
double c = 0;
double discriminant = 0;
double d = 0;

System.out.print("Enter the value of a : ");
a = input.nextDouble();

System.out.print("Enter the value of b : ");
b = input.nextDouble();

System.out.print("Enter the value of c : ");
c = input.nextDouble();

discriminant = (b * b - 4 * a * c);

d = Math.sqrt(discriminant);

if (discriminant >= 0.0) {
System.out.println("First root of the equation : "
+(-b + d) / (2.0*a));

System.out.println("Second root of the equation : "
+(-b - d) / (2.0*a));
}
else
{
System.out.println("The roots are not real numbers.");
}
}
}

```

Output of the program :